#1 2018-01-25 17:27:45

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Massive coincidences!

28.04.2015 i was diagnosed with three mental disorders: F84.5 (Asperger's syndrome), F42.2 (mixed obsessive-compulsive disorder) and F21 (schizotypal disorder) (codes are from ICD-10). I quickly said to the psychiatrist about the geometrical sequence formed by the numbers in the codes of disorders with which I was diagnosed. The geometrical sequence is 21, 42, 84. In addition, phrases: 21, 42.2, 84.5 can be formed by numbers and dots in the dates: 28.04.2015 (21 - 28.04.2015, 42.2 - 28.04.2015 (there are two numbers 2 in the date 28.04.2015), 84.5 - 28.04.2015).

My coincidences started about 18.09.2014 - 19.09.2014. After that day I had 5 visits with my former psychiatrist (first visit with that psychiatrist was probably in 2009). Dates of these 5 visits were:
- 21.10.2014 (postponed from 7.10.2014)
- 27.01.2015
- 28.05.2015
- 21.07.2015
- 08.12.2015
In these dates the numbers 3, 6 and 9 do not occur at all while all other numbers occur at least two times! 3, 6, 9 is "Tesla's arithmetical sequence" ("If you only knew the magnificence of the 3, 6 and 9, then you would have a key to the universe." - Nikola Tesla).

Another "important" sequence is 33, 42, 51. It is an arithmetical sequence. When I was about 13 - 15 years old I "invented" stupid meanings for the names of chemical elements which have atomic numbers 33, 42 and 51. Second (middle) term of this sequence is the same as in the sequence 21, 42, 84. The sequence 33, 42, 51 is coincident with "aritmetical Tesla's sequence" 3, 6, 9 and also in some way with 21.7 and 21, 42, 84.
1. There are 3 terms in 33, 42, 51 sequence.
2. There are 6 digits in 33, 42, 51 sequence.
3. The common difference of 33, 42, 51 sequence is 9.
4. Sum of digits forming 33, 42, 51 sequence is 18 = 3+6+9.
5. The difference between the largest and the smallest member of 33, 42, 51 sequence is 18 = 3+6+9 = 51-33.
6. Arithmetical means of digits in numbers forming 33, 42, 51 sequence are 3:
(3+3):2 = 6:2 = 3
(4+2):2 = 6:2 = 3
(5+1):2 = 6:2 = 3
7. Sums of digits in numbers forming 33, 42, 51 sequence are 6:
3+3 = 6
4+2 = 6
5+1 = 6
8. Sum of numbers 33, 42, 51 is 126. 126 is divisible by 3, 6, 9, 18 and 7, 14, 21, 42!
126:3 = 42 (aritmentical mean of 33, 42, 51 sequence and middle member of that sequence)
126:6 = 21
126:9 = 14 (21-7 = (21+7):2, arithmetical mean of 21 and 7)
126:18 = 7
126:7 = 18 = 3+6+9 (sum of 3, 6, 9 sequence)
126:14 = 9
126:21 = 6 (aritmetical mean of 3, 6, 9 sequence)
126:42 = 3
Sum of digits in the number 126 is 9, their arithmetical mean is 3.
9. First digits of numbers 33, 42, 51 form arithmetical sequence with sum 12 (3+9) - 3, 4, 5. Second digits of numbers 33, 42, 51 form arithmetical sequence with sum 6 - 3, 2, 1. Arithmetical mean of 12 and 6 is 9.
3+4+5 = 12
3+2+1 = 6
33+42+51 = 126
10. Chemical element with atomic number (Z) 33 is in 4 period of the periodic table and chemical elements with atomic numbers 42 and 51 are in 5 period. Sum of 4 and 5 is 9. When we count 5 two times, we will receive 14 (21-7).
11. Chemical element with atomic number (Z) 42 is in 6 group of the periodic table and chemical elements with atomic numbers 33 and 51 are in 15 group. Sum of 6 and 15 is 21. When we count 15 two times, we will receive 36 (2*(3+6+9)).
12. Sum of the largest and the smallest term of 33, 42, 51 sequence is 84 (33+51).

#2 2018-01-25 17:28:30

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Re: Massive coincidences!

21, 42, 84 is unusual geometrical sequence.
First digits in numbers forming it forms a geometrical sequence with sum 14 (21-7 = (21+7):2) - 2, 4, 8.
Second digits also form a geometrical sequence. Its sum is 7 - 1, 2, 4.
Sum of numbers forming 21, 42, 84 sequence is 147 (21*7).
2+4+8 = 14
1+2+4 = 7
21+42+84 = 147
Arithmetical mean of the terms of the sequence 21, 42, 84 is 49 (7*7 = (21*7):(21:7)).
Sum of arithmetical mean of 21, 42, 84 and sum of numbers forming that sequence is 196 (147+49 = (21-7)*(21-7) = 14*14).

Sums of digits in 21, 42, 84 sequence form a geometrical sequence which has the sum 21 and arithmetical mean 7:
2+1 = 3
4+2 = 6
8+4 = 12
3+6+12 = 21, 21:3 = 7

Products  of digits in 21, 42, 84 sequence form a geometrical sequence which has the sum 42 and arithmetical mean 14 (21-7, 14 is also the arithmetical mean of numbers 21 and 7):
2*1 = 2
4*2 = 8
8*4 = 32
2+8+32 = 42, 42:3 = 14

Numbers of sequence 21, 42, 84 read backwards form geometrical sequence which has the sum 84 and arithmetical mean 28 (21+7):
21 - 12
42 - 24
84 - 48
12, 24, 48 - geometrical sequence. 12+24+48 = 84, 84:3 = 28

Sum of digits before the dots or in first part of the diagnostic codes in phrase F84.5, F42.2, F21 is 21 (8+4+4+2+2+1). Sum of digits after the dots is 7 (2+5).

From the digits of 21, 42, 84 sequence a geometrical sequence which has 4 members can be formed: 1, 2, 4, 8.

#3 2018-01-25 17:29:22

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Re: Massive coincidences!

(2*1)2:1) = 2 : 2 = 1
(4*2)4:2) = 8 : 2 = 4
(8*4)8:4) = 32 : 2 = 16
1, 4, 16 - geometrical sequence with sum 21 and arithmetic mean 7.

(2+1)*(2:1) = 3*2 = 6
(4+2)*(4:2) = 6*2 = 12
(8+4)*(8:4) = 12*2 = 24
6, 12, 24 - geometrical sequence with sum 42 ((21-7)*(21:7)) and arithmetic mean 14 (21-7).

(2*1)*(2:1) = 2*2 = 4
(4*2)*(4:2) = 8*2 = 16
(8*4)*(8:4) = 32*2 = 64
4, 16, 64 - geometrical sequence with sum 84 ((21+7)*(21-7)) and arithmetic mean 28 (21+7).

21:(2+1) = 21:3 = 7
42:(4+2) = 42:6 = 7
84:(8+4) = 84:12 = 7
7, 7, 7 - geometrical or arithmetical sequence (constant) with sum 21 and arithmetic mean 7.

21:(2-1) = 21:1 = 21
42:(4-2) = 42:2 = 21
84:(8-4) = 84:4 = 21
21, 21, 21 - geometrical or arithmetical sequence (constant) with sum 63 (21*(21:7)) and arithmetic mean 21.

21*(2-1) = 21*1 = 21
42*(4-2) = 42*2 = 84
84*(8-4) = 84*4 = 336
21, 84, 336 - geometrical sequence with sum 441 (21*21) and arithmetic mean 147 (21*7).

(2+1)*(2-1) = 3*1 = 3
(4+2)*(4-2) = 6*2 = 12
(8+4)*(8-4) = 12*4 = 48
3, 12, 48 - geometrical sequence with sum 63 (21*(21:7)) and arithmetic mean 21.

#4 2018-01-25 17:30:34

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Re: Massive coincidences!

(repeated):
(2*1) : (2:1) = 2 : 2 = 1
(4*2) : (4:2) = 8 : 2 = 4
(8*4) : (8:4) = 32 : 2 = 16
1, 4, 16 - geometrical sequence with sum 21 and arithmetic mean 7.

2-1 = 1
4-2 = 2
8-4 = 4
1, 2, 4 - geometrical sequence with sum 7 and arithmetic mean 7/3 (7:(21:7)).

(2-1)*(2-1) = 1*1 = 1
(4-2)*(4-2) = 2*2 = 4
(8-4)*(8-4) = 4*4 = 16
1, 4, 16 - geometrical sequence with sum 21 and arithmetic mean 7.

(2:1) = 2
(4:2) = 2
(8:4) = 2
2, 2, 2 - geometrical or arithmetical sequence (constant) with sum 6 (21 is the triangular number for 6) and arithmetic mean 2 ((21+7):(21-7)).

(2*1)*(2*1) = 2*2 = 4
(4*2)*(4*2) = 8*8 = 64
(8*4)*(8*4) = 32*32 = 1024
4, 64, 1024 - geometrical sequence with sum 1092. 1092 is divisible by 84 (and 42 and 21).

(2+1)*(2+1) = 3*3 = 9
(4+2)*(4+2) = 6*6 = 36
(8+4)*(8+4) = 12*12 = 144
9, 36, 144 - geometrical sequence with sum 189 (21*9) and arithmetic mean 63 (21*3).

From the digits of 21, 42, 84 sequence there can be formed arithmetical sequences: 12, 28, 44 (common difference 16, sum 84, arithmetic mean 28) and 14, 28, 42 (common difference 14, sum 84, arithmetic mean 28). If we read these sequences backwards, we will have numbers which give sum 147: 44, 82, 21 (sum is 44+82+21 = 147) and 24, 82, 41 (sum is 24+82+41 = 147). When we sum sequences 12, 28, 44 and 14, 28, 42, we receive another arithmetical sequence - 26, 56, 86. Its common difference is 30 (16+14) and sum is 168 (21*8). When we read sequence 26, 56, 86 backwards, we receive another arithmetical sequence - 68, 65, 62. When we sort these numbers ascendingly, we will receive 62, 65, 68, which is arithmetical sequence with common difference 3 (which can be written as 03, the result of swapping digits in the number 30).

(2+1)*7 = 3*7 = 21
(2-1)*7 = 1*7 = 7
(2*1)*7 = 2*7 = 14
(2:1)*7 = 2*7 = 14
(21+7)+(14+14) = 28+28 = (21+7) + (21+7)

#5 2018-01-25 17:31:16

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Re: Massive coincidences!

I spend much of time thinking about these coincidences. They may cause "wasting of time" I may have thoughts like "Tesla prophesized about me when he said about 3, 6, 9", which looks crazy.

F21, F42.2, F84.5 - sums of two digits after Fs have the sum 21 - 2+1+4+2+8+4 = 21. Sum of digits after the dots in diagnostic codes is 7 - 2+5 = 7.

I had large coincidences because of 84 channel of satellite TV 18.12.2015. Two last digits in numbers representing day, month and year in that date (18.12.1015) are: 18, 12, 15. When we sort them ascendingly, we will receive 12, 15, 18. 12, 15, 18 are next three members of "arithmetic Tesla's sequence" (after 3, 6, 9)! What is more, the year 2015 is in 21st century and 21 is 7th member of that sequence! In addition, on 18.12.2015 I was after my 24th birthday and before my 25th birthday, so I was 24 years old. 24 is 8th member of the arithmetical progression started with numbers 3, 6, 9!

84 is the sum of 7 first terms of the "Tesla's arithmetical sequence" (3+6+9+12+15+18+21 = 84). Some (probably five) weeks before 18.12.2015, at the same day of week and at the similar time (hour), I heard about 3, 6, 9 in other episode of the same audition, that episode was about Tesla. During listening the audition at 18.12.2015, I was writing about my earlier coincidences, for example from 22.09.2014.

When we read numbers forming 33, 42, 51 sequence backwards, we will have another arithmetical sequence with common difference 9 - 15, 24, 33. Sum of numbers in that sequence (72) is divisible by 3, 6, 9 and (3+6+9), but is not divisible by 7 and 21. The difference between the largest and the smallest term of 15, 24, 33 sequence is 18 (33-15 = 18), as is in the case of the very coincident sequence 33, 42, 51 (51-33 = 18). Members of the sequence 15, 24, 33 are smaller than members of the sequence 33, 42, 51. Differences between members of these two arithmetical sequences are 18 (3+6+9):
33-15 = 18
42-24 = 18
51-33 = 18

#6 2018-01-26 14:59:56

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Re: Massive coincidences!

I do not want my coincidences to be some sort of magic and superstition.

My coincidences started in IX 2014. First visit with a psychiatrist after starting of my massive coincidences was planned to be on 7.10.2014, but it was postponed to 21.10.2014 (when it occurred).
The difference between 7.10.2014 and 21.10.2014 is 14 days (two weeks, 2*7).
14 is the arithmetic mean of numbers 21 and 7.
10 is the sum of digits in numbers 21 and 7 (2+1+7 = 10).
Sum of digits in number 2014 is 7: 2+0+1+4 = 7. From the digits in number 2014 we can extract geometrical sequence with sum 7 - 1, 2, 4 (numbers are sorted ascendingly).
2*14 = 28 = 21+7. 2 is the number of weeks between 7.10.2014 and 21.10.2014 and 14 is the number of days between 7.10.2014 and 21.10.2014.

Next visit with the psychiatrist after that from 21.10.2014 occurred 27.1.2015. The number representing the day is 27 and the number representing the month is 1. Sum of these two numbers is 28 (27+1), which is also sum of numbers 21 and 7.
27 is 3*3*3 and 1 is 1*1*1. 3+1 = 4

The most important visit occurred 28.4.2015. On it I received three diagnoses (and only them): F21, F42.2 and F84.5 first time in my life.
The number representing day is 28, 28 is 21+7.
Number representing month is 4. 4 is the quotient of the largest and the smallest terms of 21, 42, 84 sequence: 84:21 = 4.
In addition, the quotient of 28 and 4 is 7: 28:4 = 7.

Next visit was 21.7.2015.
21+7 = 28. The sum of numbers representing day and month in the case of date 21.7.2015 is the same as in the case of date 27.1.2015. And the date of the visit between 27.1.2015 and 21.7.2015 is 28.4.2015.

Last visit with my former psychiatrist occurred 8.12.2015. There is no 3, 6 or 9 in that date, such as in dates: 7.10.2014, 21.10.2014, 27.1.2015, 28.4.2015, 21.7.2015.

When we write dates of the visits from 27.1.2015, 28.4.2015 and 21.7.2015 one under another ascendingly, we will have 147 (21*7) formed by numbers representing months:
27.1.2015
28.4.2015
21.7.2015

Sum of digits forming the number 147 is 12 (1+4+7) and product of digits forming that number is 28 (1*4*7). Difference of 28 and 12 is 16. 16 is arithmetic mean of 28 and 4.
Numbers forming number 147 form arithmetic sequence: 1, 4, 7. Arithmetic mean of that sequence is 4.

I received F21, F42.2 and F84.5 diagnoses (an only them) not only on 28.4.2015. I probably received these three diagnoses: 05.07.2016 (the sum of digits in the date is 21 and from the digits of the date 21.7 can be formed), 30.09.2016 (the sum of digits in the date is 21 and there are 3, 6, 9 in that date and 21 can be formed by digits in that date), 31.7.2017 (all three numbers in that date are prime numbers, sum of digits in that date is 21 and from the numbers in that date 21.7 can be formed) and 13.11.2017 (all three numbers in that date are prime numbers).

Sum of numbers in 33, 42, 51 sequence is 126. 126 is 21*6. 6 is the arithmetic mean of 3, 6, 9. In the number 126 the same digits as these occurring in the phrase "21*6" are used. Sum of these digits is 9 and their arithmetic mean is 3. Arithmetic mean of arithmetic mean of the digits in number 126 and sum of digits in number 126 is 6 ((1+2+6):3 + 9 = 9:3 + 9 = 3+9, (3+9):2 = 12:2 = 6).

#7 2018-01-27 15:47:33

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Re: Massive coincidences!

I suppose that my coincidences (or at least part of them) may be the result of actions of unclean spirits. The 33, 42, 51 coincidence "has sources" in inventing evil meanings for the names of chemical elements. I regret it. It is bad that such stupid deeds occurred. Maybe satan gave me thoughts which later form the coincidences?

I may also suppose that my coincidences (or at least some of them) are proofs of existence of Divine Providence. I found that quote: A coincidence is a small miracle in which God chooses to remain anonymous (Irene Hannon).

The difference of sum of the 21, 42, 84 sequence and sum of the 33, 42, 51 sequence is 21:
(21+42+84)-(33+42+51) = 147-126 = 21
The difference of arithmetic mean of 21, 42, 84 sequence and arithmetic mean of 33, 42, 51 sequence is 7:
((21+42+84):3)-((33+42+51):3) = (147:3)-(126:3) = 49-42 = 7
The difference of the sum of digits in 21, 42, 84 sequence and the sum of digits in 33, 42, 51 sequence is 3 (21:7):
(2+1+4+2+8+4)-(3+3+4+2+5+1) = 21-18 = 3

The number 33 (the smallest number in 33, 42, 51 sequence) is composed of only one sort of digits: 3.
Arithmetic mean of the digits in the number 33 is 3:
(3+3):2 = 6:2 = 3
Sum of digits in the number 33 is 6:
3+3 = 6
Product of digits in the number 33 is 9:
3*3 = 9

Quotient of sum of numbers in 33, 42, 51 sequence and sum of digits forming that sequence is 7:
(33+42+51)3+3+4+2+5+1) = 126:18 = 7
Quotient of sum of numbers in 21, 42, 84 sequence and sum of digits forming that sequence is also 7:
(21+42+84)2+1+4+2+8+4) = 147:21 = 7
Sum of numbers in the sequence which is obtained by swapping digits in numbers 33, 42, 51 - 33, 24, 15 is 72. Sum of digits in 15, 24, 33 sequence is 18. Quotient of 72 and 18 is 4.
Sum of numbers in the sequence which is obtained by swapping digits in numbers 21, 42, 84 - 12, 24, 48 is 84. Sum of digits in 12, 24, 48 sequence is 21. Quotient of 84 and 21 is also 4.

#8 2018-01-27 15:48:49

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Re: Massive coincidences!

(repeated):
Quotient of sum of numbers in 33, 42, 51 sequence and sum of digits forming that sequence is 7:
(33+42+51) : (3+3+4+2+5+1) = 126:18 = 7
Quotient of sum of numbers in 21, 42, 84 sequence and sum of digits forming that sequence is also 7:
(21+42+84) : (2+1+4+2+8+4) = 147:21 = 7

#9 2018-01-28 19:47:15

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Re: Massive coincidences!

Product of 7 and 4 is 28 - 21+7. Quotient of 28 and 4 is 7.

I started my first "going" to day hospital (oddział dzienny in Polish) at the day 4.4.2016 and finished it at the day 24.6.2016. Sum of the digits in this date is 21, quotient of the number representing the day and the number representing the month is 4 (24:6), quotient of the number representing the year and the number representing the day is 84 - 2016:24 = 84. By swapping digits in number representing the day (24) we will receive 42.

I finished my second going to the oddział dzienny (it was the same oddział dzienny) at 27.1.2017. From that date two 21.7s can be formed!

From 30.01.2017 to 3.02.2017 I was going "on trial" to another day hospital, but I was not przyjęty (taken, accepted, adopted).

From 27.4.2017 to 24.7.2017 I was going to third oddział dzienny.
The digits in the date of beginning and the date of ending are the same (two 2s, two 7s, one 0, one 1, one 4).
The sum of numbers representing day and month is 31 in both cases (27+4 = 31 = 24+7).
The sum of digits in numbers representing day and month is 13 in both cases (2+7+4 = 13 = 2+4+7).
31 is the result of swapping digits in number 13. Both 13 and 31 are prime numbers.
2017 is also a prime numbers.
Sums of digits in entire dates 27.4.2017 and 24.7.2017 is 23 (2+7+4+2+0+1+7 = 23 = 2+4+7+2+0+1+7).
23 is also a prime number. It is a prime number which sum of digits is also a prime number (2+3 = 5). 2 and 3 are prime numbers.
Sum of digits in numbers 13 and 31 is 4. Sum of numbers 31 and 13 is 44!

#10 2018-01-29 11:58:41

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Re: Massive coincidences!

21.7.2017 I got from a psychiatrist the certificate for commission adjudicating about the level of disability on which three diagnoses were mentioned: F84.5, F42.2 and F21. In that date numbers forming phrase 21.7 occur two times (21.7.2017).

From 27.4.2017 to 24.7.2017 my fourth going to day hospital (oddział dzienny) occurred. It was third time when I was accepted (przyjęty). It was my first going to that day hospital and it was third oddział dzienny to which I was going. 2+7+4 = 2+4+7 = 13, 27+4 = 24+7 = 31, 3+1 = 1+3 = 4, 13+31 = 44.

I suppose that it is really rare to find arithmetical or geometrical sequence in codes of medical diagnoses. In my case a geometrical sequence was formed by them. I suppose that I may be the only man (or even human) who received three diagnoses (and only these three) at the same time: F21, F42 and F84.

My coincidences looked interesting for me even before start of 21.7 and 21, 42, 84 coincidences. I remember severe stimming when I had coincidences 22.09.2014. They were associated with cementeries, two Austrian men (association with Leo Kanner and Hans Asperger, two men from Polish AS forum had logins associated with their surnames) and crosses (commendations) about which I read in teletext.

My first coincidences were associated with photographies of cementeries and black cat. 19.09.2014 I saw (probably dead) black cat which lied on the road which has small traffic intensity. I also photographied Jewish cementery and a part of Catholic cementery using smartphone that day. About 11 p.m. 19.09.2014 I saw on the same smartphone photographies of cementeries (probably Jewish and Catholic) made by an Aspijka (woman with Asperger's) who wrote the book about ASD in which on the first page there was black image of cat. In addition, nick of that woman was somewhat associated with Italy and next day after 19.09.2014 my brother flied to Italy. 01.09.2016 I saw another dead black cat on field track which had very low traffic intensity. Probably next day my mother started travel to Italy.

#11 2018-01-31 22:16:37

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Re: Massive coincidences!

I am interesting how rare are cases when numbers in codes of health problems form geometrical or arithmetical sequence. What are chances that a person would receive at least three diagnoses which codes form such a sequence? 1:10 000 000? 1:100 000 000? 1:1000 000 000?

Maybe the autor of that topic (a woman, she appears to be from USA, so DSM could be used instead of ICD) was diagnosed with F21, F42 and F84 at the same time. It would be second case of it. I do not exclude the possibility that it could be the only person who was diagnosed with these diagnoses other than me. So the chance of being diagnosed with F21, F42 and F84 at the same time could be smaller than 1:3 500 000 000. Combination of pervasive developmental disorder, obsessive-compulsive disorder and schizotypal disorder may be ultra-rare.

21, 42, 84 is not a mere geometrical sequence, but "miraculous sequence" - has interesting properties described in my earlier posts in this topic.

F42.2 - mixed obsessive-compulsive disorder in ICD-10.
42:2 = 21
42*2 = 84

2015 - year in which I got F21, F42.2 and F84.5 diagnoses at the same time first time. The same digits as in number 2015 are in my birth weight written in my health certificate (2150 g).

Let's swap digits in numbers: 21, 42, 84 to make 12, 24, 48 - another geometrical sequence. Then subtract "second" numbers from first ones:
21 - 12 = 9;
42 - 24 = 18;
84 - 48 = 36;
9, 18, 36 - it is also a geometrical sequence.
Subtracting "third" numbers from second ones:
12 - 9 = 3;
24 - 18 = 6;
48 - 36 = 12;
"Fourth" numbers (3, 6, 12) also form a geometrical sequence.
Subtract "fourth" numbers from "third" ones:
9 - 3 = 6;
18 - 6 = 12;
36 - 12 = 24;
"Fifth" numbers also form a geometrical sequence: (6, 12, 24).
Subtract "fifth" numbers from "fourth" ones:
3 - 6 = -3
6 - 12 = -6
12 - 24 - -12
"Sixth" numbers also form a geometrical sequence: ((-3), (-6), (-12)).
Subtract "sixth" numbers from "fifth" ones:
6 - (-3) = 9;
12 - (-6) = 18;
24 - (-12) = 36;
"Seventh" numbers also form a geometrical sequence: (9, 18, 36).
We can make that iteration any number of times and we would always receive a geometrical sequence. There will be infinite(?) number of geometrical sequences produced that way.

#12 2018-02-01 16:45:40

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Re: Massive coincidences!

I do not want to believe in the occult despite my coinicidence because occultism is a sin. I also do not want to practice magic because of its sinfulness.

Let's swap digits in numbers: 33, 42, 51 to make 15, 24, 33 - another arithmetical sequence (with common difference 9). Then subtract "second" numbers from first ones:
33 - 15 = 18;
42 - 24 = 18;
51 - 33 = 18;
18, 18, 18 - it is also an arithmetical sequence (constant one, common differenece is 0).
Subtracting "third" numbers from second ones:
15 - 18 = -3;
24 - 18 = 6;
33 - 18 = 15;
"Fourth" numbers (-3, 6, 15) also form an arithmetical sequence with common difference 9.
Subtract "fourth" numbers from "third" ones:
18 - (-3) = 21;
18 - 6 = 12;
18 - 15 = 3;
"Fifth" numbers also form an arithmetical sequence: (21, 12, 3) - common difference -9.
Subtract "fifth" numbers from "fourth" ones:
(-3) - 21 = -24
6 - 12 = -6
15 - 3 = 12
"Sixth" numbers also form an arithmetical sequence: ((-24), (-6), (12)) - common difference 18.
Subtract "sixth" numbers from "fifth" ones:
21 - (-24) = 45;
12 - (-6) = 18;
3 - 12 = -9;
"Seventh" numbers also form an arithmetical sequence: (45, 18, -9) - common difference -27.
Subtract "seventh" numbers from "sixth" ones:
-24 - 45 = -69
-6 - 18 = -24
12 - (-9) = 21
"Eighth" numbers also form an arithmetical sequence: -69, -24, 21 - common difference 45.
It is probable that we can make that iteration any number of times and we would always receive an arithmetical sequence. There will be infinite(?) number of arithmetical sequences produced that way.

#13 2018-02-04 15:54:19

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Re: Massive coincidences!

At late spring 2015 I gave an Aspie birthday wishes on Polish Asperger's forum. The same day I saw inscription on a box for some vegetables in a shop. The inscription was quite large login of the Aspie who had birthday! In addition, I forgot to take meat from that shop and I drove back for it about 6-7 kilometers in one way.

2.4.2015 there was International Autism Day. That day I read in teletext about the visit of a president of some country in certain city in Poland.
The country from which the president was the country from which comes a login (nick) of an Aspijka who wrote an article about ASD which was presented at one of Internet sites at day 02.04.2015.
In addition, the description of the place in that Aspijka's profile was associated with the city to which the president of that foreign country arrived.

At the beginning of the ninth month of a year in 2015 an another Aspijka had a birthday.
In a public communication vehicle I saw images (or at least text with the name) of the city (it was quite far from Poland) in which that person studied.
The same day I saw surname of that Aspijka in the seat of a management (and the woman who had that surname probably had in addition two first letters of the name the same as that Aspijka).
Moreover, in later part of the same day an another woman gave me small card on which probably her name and surname were written. The name was the same as the name of Aspijka mentioned earlier. In addition, first letter of her surname could be associated with the login of that Aspijka on Polish AS forum.
Even earlier at the same day, I walked at the street which name was associated with the name of the city from which that Aspijka (at least probably) comes. When I started to ride in a bus, I also noticed an umbrella with the adverisement(?) of a product from that city.
Probably before midnight the same day I started to use toothpaste which was in packaging on which text in the language of the country in which that woman studied and which is quite far from Poland.

#14 2018-02-11 19:19:29

valkosipuli nca14

Gość

Re: Massive coincidences!

5.2.2018 (or 6.2.2018 or 7.02.2018) I thought about melting and boiling point of chemical element with atomic number 35. I might check if I know melting and boiling points of chemical elements. I plausibly remembered melting point of bromine (Z=35) as -7 °C and boiling point as 59 °C (approximate values, melting point is more precisely -7,2 °C and boiling point is 58,8 °C). "So I thought about -7 and 59". Earlier I heard piece of sound entitled "Bromine" (not 5.2.2018, but earlier in my life).
Sum of digits in number 59 is 14.
Sum of 14 and -7 is 7.
Sum of 14 and 7 (absolute value of -7 is 7) is 21. 21.7 coincidence again!

14.02.2015 I had coincidences associated with the same Aspijka as one mentioned in last part in my previous post in that topic. That day I read her blog. My grandmother told me to photograph leafless trees using my smartphone. That Aspijka had (probably leafless) tree in her picture image.
About few months earlier I had another coincidence due to this image. I read a topic started by that person on my smartphone when I was in the room in which there were many pictures of trees (or near it)!

#15 2018-04-01 18:54:03

valkosipuli nca14

Gość

Re: Massive coincidences!

There are many interesting properties of arithmetical progression 33, 42, 51. It is coincident due to three main reasons:
1. Association with "Tesla's arithmetical progression" (3, 6, 9).
- arithmetical means of digits in numbers forming 33, 42, 51 are 3
- sums of digits in numbers forming 33, 42, 51 are 6
- common difference of 33, 42, 51 is 9
- sum of digits in 33, 42, 51 is 18 (3+6+9)
- there are 3 numbers in 33, 42, 51
- there are 6 digits in 33, 42, 51
2. Association with 21.7 and geometrical sequence 21, 42, 84.
- sum of numbers in 33, 42, 51 is 126, which is 7*(3+6+9) = 7*18; 126 is divisible by 7 and the result is 18 - sum of numbers 3, 6, 9
- 126 is divisible by 21 and the result is arithmetical mean of 3, 6, 9 - 6 (126/21 = 6)
- 42 is the middle member of arithmetical progression 33, 42, 51
- sum of two extreme terms of 33, 42, 51 is 84
- sum of 33, 42, 51 is (21+42+84) - 21 = 147 - 21 = 126
- arithmetical mean of 33, 42, 51 is ((21+42+84)/3) - 7) = (147/3) - 7 = 49 - 7 = 42
- sum of digits of 33, 42, 51 is 18, which is ((2+1+4+2+8+4) - (21/7)) = 21 - 3
3. Fact of the possibility of forming other arithmetical sequences from digits of 33, 42, 51.

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